What are the solutions to the equation 2x^2-57x+216=0 ?

The solutions to the equation 2x^2-57x+216=0 are x=24,x= 9/2

Find the zeros of 2x^2-57x+216=0

The zeros of 2x^2-57x+216=0 are x=24,x= 9/2

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2 x^{2} - 57 x + 216 = 0

x = 24, x = \frac{9}{2}

Decimal Notation

x = 24, x = 4.5

Solution steps

2 x^{2} - 57 x + 216 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 57 ) \pm ( - 57 ) ^{2} - 4 \cdot 2 \cdot 216}{2 \cdot 2}

(- 57)^{2} - 4 \cdot 2 \cdot 216 = 39

x_{1, 2} = \frac{- ( - 57 ) \pm 39}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 57 ) + 39}{2 \cdot 2}, x_{2} = \frac{- ( - 57 ) - 39}{2 \cdot 2}

x = \frac{- ( - 57 ) + 39}{2 \cdot 2} : 24

x = \frac{- ( - 57 ) - 39}{2 \cdot 2} : \frac{9}{2}

The solutions to the quadratic equation are:

x = 24, x = \frac{9}{2}

x^{2} + 4 x + 4

x^{2} + 4 x + 6

x^{2} + 4 x + 9

s^{2} + 4 s + 2 = 0

c^{2} - 20 = 44

What are the solutions to the equation 2x^2-57x+216=0 ?
The solutions to the equation 2x^2-57x+216=0 are x=24,x= 9/2
Find the zeros of 2x^2-57x+216=0
The zeros of 2x^2-57x+216=0 are x=24,x= 9/2