What are the solutions to the equation 0=x^2-x-12 ?

The solutions to the equation 0=x^2-x-12 are x=4,x=-3

Find the zeros of 0=x^2-x-12

The zeros of 0=x^2-x-12 are x=4,x=-3

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0 = x^{2} - x - 12

x = 4, x = - 3

Solution steps

0 = x^{2} - x - 12

Switch sides

x^{2} - x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 12) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 1}

x = \frac{- ( - 1 ) + 7}{2 \cdot 1} : 4

x = \frac{- ( - 1 ) - 7}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 4, x = - 3

(2 x + 4) (x + 7) = 2

- x^{2} + 6 = 0

- 16 x^{2} = 1

x^{2} + 7 x + 2

2 x^{2} - 3 x - 5 = 0

What are the solutions to the equation 0=x^2-x-12 ?
The solutions to the equation 0=x^2-x-12 are x=4,x=-3
Find the zeros of 0=x^2-x-12
The zeros of 0=x^2-x-12 are x=4,x=-3