What are the solutions to the equation x^2+16x+2=0 ?

The solutions to the equation x^2+16x+2=0 are x=-8+sqrt(62),x=-8-sqrt(62)

Find the zeros of x^2+16x+2=0

The zeros of x^2+16x+2=0 are x=-8+sqrt(62),x=-8-sqrt(62)

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x^{2} + 16 x + 2 = 0

x = - 8 + 62, x = - 8 - 62

Decimal Notation

x = - 0.12599 \dots, x = - 15.87400 \dots

Solution steps

x^{2} + 16 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 2 = 262

x_{1, 2} = \frac{- 16 \pm 2 62}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 62}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 62}{2 \cdot 1}

x = \frac{- 16 + 2 62}{2 \cdot 1} : - 8 + 62

x = \frac{- 16 - 2 62}{2 \cdot 1} : - 8 - 62

The solutions to the quadratic equation are:

x = - 8 + 62, x = - 8 - 62

9 x^{2} - 6 x + 1 = 2

s^{2} + 12 s + 20 = 0

x^{2} + 6 x + 3 = 0

x^{2} - 6 x + 13

x^{2} + 6 x + 2

What are the solutions to the equation x^2+16x+2=0 ?
The solutions to the equation x^2+16x+2=0 are x=-8+sqrt(62),x=-8-sqrt(62)
Find the zeros of x^2+16x+2=0
The zeros of x^2+16x+2=0 are x=-8+sqrt(62),x=-8-sqrt(62)