What are the solutions to the equation 6x^2-42x+60=0 ?

The solutions to the equation 6x^2-42x+60=0 are x=5,x=2

Find the zeros of 6x^2-42x+60=0

The zeros of 6x^2-42x+60=0 are x=5,x=2

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6 x^{2} - 42 x + 60 = 0

x = 5, x = 2

Solution steps

6 x^{2} - 42 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 42 ) \pm ( - 42 ) ^{2} - 4 \cdot 6 \cdot 60}{2 \cdot 6}

(- 42)^{2} - 4 \cdot 6 \cdot 60 = 18

x_{1, 2} = \frac{- ( - 42 ) \pm 18}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 42 ) + 18}{2 \cdot 6}, x_{2} = \frac{- ( - 42 ) - 18}{2 \cdot 6}

x = \frac{- ( - 42 ) + 18}{2 \cdot 6} : 5

x = \frac{- ( - 42 ) - 18}{2 \cdot 6} : 2

The solutions to the quadratic equation are:

x = 5, x = 2

\frac{1.4 \cdot 1 0 ^{- 8}}{3.5 \cdot 1 0 ^{- 13}}

16 a^{2} - 49 b^{2}

x^{2} y - y^{2} x

- 91 x^{2} + 108 x - 32

3 \leq 12

What are the solutions to the equation 6x^2-42x+60=0 ?
The solutions to the equation 6x^2-42x+60=0 are x=5,x=2
Find the zeros of 6x^2-42x+60=0
The zeros of 6x^2-42x+60=0 are x=5,x=2