What are the solutions to the equation 5x^2+4x=0 ?

The solutions to the equation 5x^2+4x=0 are x=0,x=-4/5

Find the zeros of 5x^2+4x=0

The zeros of 5x^2+4x=0 are x=0,x=-4/5

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5 x^{2} + 4 x = 0

x = 0, x = - \frac{4}{5}

Decimal Notation

x = 0, x = - 0.8

Solution steps

5 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

4^{2} - 4 \cdot 5 \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 \cdot 5}, x_{2} = \frac{- 4 - 4}{2 \cdot 5}

x = \frac{- 4 + 4}{2 \cdot 5} : 0

x = \frac{- 4 - 4}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

x = 0, x = - \frac{4}{5}

x, y^{2} - x^{2} = x y + x^{2} y

5 x^{2} + 8 x + 5 = 0

(q - 2)^{2} + 8 = 44

x^{2} + \frac{1}{3} x + 3

x^{2} - 41 x + 400 = 0

What are the solutions to the equation 5x^2+4x=0 ?
The solutions to the equation 5x^2+4x=0 are x=0,x=-4/5
Find the zeros of 5x^2+4x=0
The zeros of 5x^2+4x=0 are x=0,x=-4/5