What are the solutions to the equation x=4x-x^2 ?

The solutions to the equation x=4x-x^2 are x=0,x=3

Find the zeros of x=4x-x^2

The zeros of x=4x-x^2 are x=0,x=3

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x = 4 x - x^{2}

x = 0, x = 3

Solution steps

x = 4 x - x^{2}

Switch sides

4 x - x^{2} = x

Move

x

to the left side

- x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 ( - 1 )}, x_{2} = \frac{- 3 - 3}{2 ( - 1 )}

x = \frac{- 3 + 3}{2 ( - 1 )} : 0

x = \frac{- 3 - 3}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = 0, x = 3

x^{2} + 10 x + 25 = 121

x^{2} - 4 x + 13

x^{2} + x - 4 b x = b - 3 b^{2}

x^{2} - 6 x + 10 = 0

- y^{2} + 2 = 12 y - 7

What are the solutions to the equation x=4x-x^2 ?
The solutions to the equation x=4x-x^2 are x=0,x=3
Find the zeros of x=4x-x^2
The zeros of x=4x-x^2 are x=0,x=3