What are the solutions to the equation 4(x-8)^2-10=14 ?

The solutions to the equation 4(x-8)^2-10=14 are x=sqrt(6)+8,x=-sqrt(6)+8

Find the zeros of 4(x-8)^2-10=14

The zeros of 4(x-8)^2-10=14 are x=sqrt(6)+8,x=-sqrt(6)+8

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4 (x - 8)^{2} - 10 = 14

x = 6 + 8, x = - 6 + 8

Decimal Notation

x = 10.44948 \dots, x = 5.55051 \dots

Solution steps

4 (x - 8)^{2} - 10 = 14

Move

10

to the right side

4 (x - 8)^{2} = 24

Divide both sides by

4

(x - 8)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 8 = 6 : x = 6 + 8

Solve

x - 8 = - 6 : x = - 6 + 8

The solutions to the quadratic equation are:

x = 6 + 8, x = - 6 + 8

3 b^{2} + b - 10 = 0

12 x^{2} - 144 x + 324 = 0

x^{2} = 4 - 3 x

15 x^{2} = 2 (4 - 7 x)

9 x^{2} - 81 x = 0

What are the solutions to the equation 4(x-8)^2-10=14 ?
The solutions to the equation 4(x-8)^2-10=14 are x=sqrt(6)+8,x=-sqrt(6)+8
Find the zeros of 4(x-8)^2-10=14
The zeros of 4(x-8)^2-10=14 are x=sqrt(6)+8,x=-sqrt(6)+8