What are the solutions to the equation x^2+3x=-5 ?

The solutions to the equation x^2+3x=-5 are x=-3/2+i(sqrt(11))/2 ,x=-3/2-i(sqrt(11))/2

Find the zeros of x^2+3x=-5

The zeros of x^2+3x=-5 are x=-3/2+i(sqrt(11))/2 ,x=-3/2-i(sqrt(11))/2

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x^{2} + 3 x = - 5

x = - \frac{3}{2} + i \frac{11}{2}, x = - \frac{3}{2} - i \frac{11}{2}

Solution steps

x^{2} + 3 x = - 5

Move

5

to the left side

x^{2} + 3 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

3^{2} - 4 \cdot 1 \cdot 5 : 11 i

x_{1, 2} = \frac{- 3 \pm 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 11 i}{2 \cdot 1}, x_{2} = \frac{- 3 - 11 i}{2 \cdot 1}

x = \frac{- 3 + 11 i}{2 \cdot 1} : - \frac{3}{2} + i \frac{11}{2}

x = \frac{- 3 - 11 i}{2 \cdot 1} : - \frac{3}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{11}{2}, x = - \frac{3}{2} - i \frac{11}{2}

3 x^{2} = 10 x - 7

v, E = \frac{1}{2} m v^{2} + m g h

(3 x + 8)^{2} - 10 = - 6

12 x^{2} - 5 = 0

x^{2} - x + 5

What are the solutions to the equation x^2+3x=-5 ?
The solutions to the equation x^2+3x=-5 are x=-3/2+i(sqrt(11))/2 ,x=-3/2-i(sqrt(11))/2
Find the zeros of x^2+3x=-5
The zeros of x^2+3x=-5 are x=-3/2+i(sqrt(11))/2 ,x=-3/2-i(sqrt(11))/2