What are the solutions to the equation solvefor a,a^2=c^2-b^2 ?

The solutions to the equation solvefor a,a^2=c^2-b^2 are a=sqrt(c^2-b^2),a=-sqrt(c^2-b^2)

Find the zeros of solvefor a,a^2=c^2-b^2

The zeros of solvefor a,a^2=c^2-b^2 are a=sqrt(c^2-b^2),a=-sqrt(c^2-b^2)

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solve for

a, a^{2} = c^{2} - b^{2}

a = c^{2} - b^{2}, a = - c^{2} - b^{2}

Solution steps

a^{2} = c^{2} - b^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = c^{2} - b^{2}, a = - c^{2} - b^{2}

x^{2} = \frac{25}{4}

9 - 15 x^{2} = 13 + 7 x^{2}

16 d^{2} - 81 = 0

0 = - x^{2} - 4

x^{2} + 29 = - 12 x

What are the solutions to the equation solvefor a,a^2=c^2-b^2 ?
The solutions to the equation solvefor a,a^2=c^2-b^2 are a=sqrt(c^2-b^2),a=-sqrt(c^2-b^2)
Find the zeros of solvefor a,a^2=c^2-b^2
The zeros of solvefor a,a^2=c^2-b^2 are a=sqrt(c^2-b^2),a=-sqrt(c^2-b^2)