What are the solutions to the equation 104-84x+12x^2=0 ?

The solutions to the equation 104-84x+12x^2=0 are x=(21+sqrt(129))/6 ,x=(21-sqrt(129))/6

Find the zeros of 104-84x+12x^2=0

The zeros of 104-84x+12x^2=0 are x=(21+sqrt(129))/6 ,x=(21-sqrt(129))/6

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104 - 84 x + 12 x^{2} = 0

x = \frac{21 + 129}{6}, x = \frac{21 - 129}{6}

Decimal Notation

x = 5.39296 \dots, x = 1.60703 \dots

Solution steps

104 - 84 x + 12 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 84 x + 104 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 84 ) \pm ( - 84 ) ^{2} - 4 \cdot 12 \cdot 104}{2 \cdot 12}

(- 84)^{2} - 4 \cdot 12 \cdot 104 = 4129

x_{1, 2} = \frac{- ( - 84 ) \pm 4 129}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 84 ) + 4 129}{2 \cdot 12}, x_{2} = \frac{- ( - 84 ) - 4 129}{2 \cdot 12}

x = \frac{- ( - 84 ) + 4 129}{2 \cdot 12} : \frac{21 + 129}{6}

x = \frac{- ( - 84 ) - 4 129}{2 \cdot 12} : \frac{21 - 129}{6}

The solutions to the quadratic equation are:

x = \frac{21 + 129}{6}, x = \frac{21 - 129}{6}

2 x^{2} - 8 x + 5

- 23 = x^{2} + 8 x

- x^{2} + 5 x = (x - 3)^{2}

x, y^{3} + y = 3 x^{2} + 5 x

6 a^{2} + a - 15 = 0

What are the solutions to the equation 104-84x+12x^2=0 ?
The solutions to the equation 104-84x+12x^2=0 are x=(21+sqrt(129))/6 ,x=(21-sqrt(129))/6
Find the zeros of 104-84x+12x^2=0
The zeros of 104-84x+12x^2=0 are x=(21+sqrt(129))/6 ,x=(21-sqrt(129))/6