What are the solutions to the equation -8x^2+16x-1=0 ?

The solutions to the equation -8x^2+16x-1=0 are x=(4-sqrt(14))/4 ,x=(4+sqrt(14))/4

Find the zeros of -8x^2+16x-1=0

The zeros of -8x^2+16x-1=0 are x=(4-sqrt(14))/4 ,x=(4+sqrt(14))/4

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- 8 x^{2} + 16 x - 1 = 0

x = \frac{4 - 14}{4}, x = \frac{4 + 14}{4}

Decimal Notation

x = 0.06458 \dots, x = 1.93541 \dots

Solution steps

- 8 x^{2} + 16 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 8 ) ( - 1 )}{2 ( - 8 )}

1 6^{2} - 4 (- 8) (- 1) = 414

x_{1, 2} = \frac{- 16 \pm 4 14}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 16 + 4 14}{2 ( - 8 )}, x_{2} = \frac{- 16 - 4 14}{2 ( - 8 )}

x = \frac{- 16 + 4 14}{2 ( - 8 )} : \frac{4 - 14}{4}

x = \frac{- 16 - 4 14}{2 ( - 8 )} : \frac{4 + 14}{4}

The solutions to the quadratic equation are:

x = \frac{4 - 14}{4}, x = \frac{4 + 14}{4}

x^{2} - 3 x - 28 = 0

8 x^{2} - 8 = 0

x 0.9 (x + 1) = 25 + x

16 x^{2} + 40 x + 27 = 0

x^{2} - 10 x = 15

What are the solutions to the equation -8x^2+16x-1=0 ?
The solutions to the equation -8x^2+16x-1=0 are x=(4-sqrt(14))/4 ,x=(4+sqrt(14))/4
Find the zeros of -8x^2+16x-1=0
The zeros of -8x^2+16x-1=0 are x=(4-sqrt(14))/4 ,x=(4+sqrt(14))/4