What are the solutions to the equation 4x^2+9x-10=0 ?

The solutions to the equation 4x^2+9x-10=0 are x=(-9+sqrt(241))/8 ,x=(-9-sqrt(241))/8

Find the zeros of 4x^2+9x-10=0

The zeros of 4x^2+9x-10=0 are x=(-9+sqrt(241))/8 ,x=(-9-sqrt(241))/8

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4 x^{2} + 9 x - 10 = 0

x = \frac{- 9 + 241}{8}, x = \frac{- 9 - 241}{8}

Solution steps

4 x^{2} + 9 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 ( - 10 )}{2 \cdot 4}

9^{2} - 4 \cdot 4 (- 10) = 241

x_{1, 2} = \frac{- 9 \pm 241}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 9 + 241}{2 \cdot 4}, x_{2} = \frac{- 9 - 241}{2 \cdot 4}

x = \frac{- 9 + 241}{2 \cdot 4} : \frac{- 9 + 241}{8}

x = \frac{- 9 - 241}{2 \cdot 4} : \frac{- 9 - 241}{8}

The solutions to the quadratic equation are:

x = \frac{- 9 + 241}{8}, x = \frac{- 9 - 241}{8}

3 (x + 3) = 7 (x - 2)

- 3 \cdot \frac{3}{2}

∣ x + 7 ∣ > 2

\frac{1}{6} + \frac{1}{5}

\frac{3}{10} - \frac{7}{15}

What are the solutions to the equation 4x^2+9x-10=0 ?
The solutions to the equation 4x^2+9x-10=0 are x=(-9+sqrt(241))/8 ,x=(-9-sqrt(241))/8
Find the zeros of 4x^2+9x-10=0
The zeros of 4x^2+9x-10=0 are x=(-9+sqrt(241))/8 ,x=(-9-sqrt(241))/8