What are the solutions to the equation -17x^2+64x=48 ?

The solutions to the equation -17x^2+64x=48 are x=(4(8-sqrt(13)))/(17),x=(4(8+sqrt(13)))/(17)

Find the zeros of -17x^2+64x=48

The zeros of -17x^2+64x=48 are x=(4(8-sqrt(13)))/(17),x=(4(8+sqrt(13)))/(17)

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- 17 x^{2} + 64 x = 48

x = \frac{4 ( 8 - 13 )}{17}, x = \frac{4 ( 8 + 13 )}{17}

Decimal Notation

x = 1.03398 \dots, x = 2.73071 \dots

Solution steps

- 17 x^{2} + 64 x = 48

Move

48

to the left side

- 17 x^{2} + 64 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 ( - 17 ) ( - 48 )}{2 ( - 17 )}

6 4^{2} - 4 (- 17) (- 48) = 813

x_{1, 2} = \frac{- 64 \pm 8 13}{2 ( - 17 )}

Separate the solutions

x_{1} = \frac{- 64 + 8 13}{2 ( - 17 )}, x_{2} = \frac{- 64 - 8 13}{2 ( - 17 )}

x = \frac{- 64 + 8 13}{2 ( - 17 )} : \frac{4 ( 8 - 13 )}{17}

x = \frac{- 64 - 8 13}{2 ( - 17 )} : \frac{4 ( 8 + 13 )}{17}

The solutions to the quadratic equation are:

x = \frac{4 ( 8 - 13 )}{17}, x = \frac{4 ( 8 + 13 )}{17}

3 x^{2} - 12 x - 11 = 0

x^{2} = 8 x + 4

(5 x + 8)^{2} - 8 = 35

x, x y = (x - y)^{2} + 1

3 x^{2} - 14 x + 10 = 0

What are the solutions to the equation -17x^2+64x=48 ?
The solutions to the equation -17x^2+64x=48 are x=(4(8-sqrt(13)))/(17),x=(4(8+sqrt(13)))/(17)
Find the zeros of -17x^2+64x=48
The zeros of -17x^2+64x=48 are x=(4(8-sqrt(13)))/(17),x=(4(8+sqrt(13)))/(17)