What are the solutions to the equation 7x^2-9x+1=0 ?

The solutions to the equation 7x^2-9x+1=0 are x=(9+sqrt(53))/(14),x=(9-sqrt(53))/(14)

Find the zeros of 7x^2-9x+1=0

The zeros of 7x^2-9x+1=0 are x=(9+sqrt(53))/(14),x=(9-sqrt(53))/(14)

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7 x^{2} - 9 x + 1 = 0

x = \frac{9 + 53}{14}, x = \frac{9 - 53}{14}

Decimal Notation

x = 1.16286 \dots, x = 0.12284 \dots

Solution steps

7 x^{2} - 9 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 7 \cdot 1}{2 \cdot 7}

(- 9)^{2} - 4 \cdot 7 \cdot 1 = 53

x_{1, 2} = \frac{- ( - 9 ) \pm 53}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 53}{2 \cdot 7}, x_{2} = \frac{- ( - 9 ) - 53}{2 \cdot 7}

x = \frac{- ( - 9 ) + 53}{2 \cdot 7} : \frac{9 + 53}{14}

x = \frac{- ( - 9 ) - 53}{2 \cdot 7} : \frac{9 - 53}{14}

The solutions to the quadratic equation are:

x = \frac{9 + 53}{14}, x = \frac{9 - 53}{14}

12 y^{2} - 24 y - 36 = 0

x^{2} + 2 x - 3 = 0

x^{2} + 2 x - 1 = 0

15 x^{2} - x - 2 = - 8 x

x^{2} + 4 x + 15 = 0

What are the solutions to the equation 7x^2-9x+1=0 ?
The solutions to the equation 7x^2-9x+1=0 are x=(9+sqrt(53))/(14),x=(9-sqrt(53))/(14)
Find the zeros of 7x^2-9x+1=0
The zeros of 7x^2-9x+1=0 are x=(9+sqrt(53))/(14),x=(9-sqrt(53))/(14)