What are the solutions to the equation -2x^2+2x-1=0 ?

The solutions to the equation -2x^2+2x-1=0 are x= 1/2-i 1/2 ,x= 1/2+i 1/2

Find the zeros of -2x^2+2x-1=0

The zeros of -2x^2+2x-1=0 are x= 1/2-i 1/2 ,x= 1/2+i 1/2

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- 2 x^{2} + 2 x - 1 = 0

x = \frac{1}{2} - i \frac{1}{2}, x = \frac{1}{2} + i \frac{1}{2}

Solution steps

- 2 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 2 ) ( - 1 )}{2 ( - 2 )}

Simplify

2^{2} - 4 (- 2) (- 1) : 2 i

x_{1, 2} = \frac{- 2 \pm 2 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 i}{2 ( - 2 )}, x_{2} = \frac{- 2 - 2 i}{2 ( - 2 )}

x = \frac{- 2 + 2 i}{2 ( - 2 )} : \frac{1}{2} - i \frac{1}{2}

x = \frac{- 2 - 2 i}{2 ( - 2 )} : \frac{1}{2} + i \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} - i \frac{1}{2}, x = \frac{1}{2} + i \frac{1}{2}

- 36 x^{2} + 100 = 0

144 x^{2} - 100 = 0

s^{2} + 8 s + 25

x^{2} + x - 15 = 0

(8 x^{2} - 15 x) - (x^{2} - 27 x) = a x^{2} + b x

What are the solutions to the equation -2x^2+2x-1=0 ?
The solutions to the equation -2x^2+2x-1=0 are x= 1/2-i 1/2 ,x= 1/2+i 1/2
Find the zeros of -2x^2+2x-1=0
The zeros of -2x^2+2x-1=0 are x= 1/2-i 1/2 ,x= 1/2+i 1/2