What are the solutions to the equation solvefor x,9y^2-18y-16x^2+32x-7=0 ?

The solutions to the equation solvefor x,9y^2-18y-16x^2+32x-7=0 are x=-(3y-7)/4 ,x=(3y+1)/4

Find the zeros of solvefor x,9y^2-18y-16x^2+32x-7=0

The zeros of solvefor x,9y^2-18y-16x^2+32x-7=0 are x=-(3y-7)/4 ,x=(3y+1)/4

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solve for

x, 9 y^{2} - 18 y - 16 x^{2} + 32 x - 7 = 0

x = - \frac{3 y - 7}{4}, x = \frac{3 y + 1}{4}

Solution steps

9 y^{2} - 18 y - 16 x^{2} + 32 x - 7 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 x^{2} + 32 x + 9 y^{2} - 18 y - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 ( - 16 ) ( 9 y ^{2} - 18 y - 7 )}{2 ( - 16 )}

Simplify

3 2^{2} - 4 (- 16) (9 y^{2} - 18 y - 7) : 24 (y - 1)

x_{1, 2} = \frac{- 32 \pm 24 ( y - 1 )}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 32 + 24 ( y - 1 )}{2 ( - 16 )}, x_{2} = \frac{- 32 - 24 ( y - 1 )}{2 ( - 16 )}

x = \frac{- 32 + 24 ( y - 1 )}{2 ( - 16 )} : - \frac{3 y - 7}{4}

x = \frac{- 32 - 24 ( y - 1 )}{2 ( - 16 )} : \frac{3 y + 1}{4}

The solutions to the quadratic equation are:

x = - \frac{3 y - 7}{4}, x = \frac{3 y + 1}{4}

(x - 2) (x - 1) = 0

- x^{2} = - 1

x, z = 3 x^{2}

x, 3 x^{2} z - x^{2} y^{2} + 2 z^{3} + 3 yz - 5 = 0

t, t^{2} = - 4 x

What are the solutions to the equation solvefor x,9y^2-18y-16x^2+32x-7=0 ?
The solutions to the equation solvefor x,9y^2-18y-16x^2+32x-7=0 are x=-(3y-7)/4 ,x=(3y+1)/4
Find the zeros of solvefor x,9y^2-18y-16x^2+32x-7=0
The zeros of solvefor x,9y^2-18y-16x^2+32x-7=0 are x=-(3y-7)/4 ,x=(3y+1)/4