What are the solutions to the equation 5^2+8^2=x^2 ?

The solutions to the equation 5^2+8^2=x^2 are x=sqrt(89),x=-sqrt(89)

Find the zeros of 5^2+8^2=x^2

The zeros of 5^2+8^2=x^2 are x=sqrt(89),x=-sqrt(89)

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5^{2} + 8^{2} = x^{2}

x = 89, x = - 89

Decimal Notation

x = 9.43398 \dots, x = - 9.43398 \dots

Solution steps

5^{2} + 8^{2} = x^{2}

Switch sides

x^{2} = 5^{2} + 8^{2}

Simplify

5^{2} + 8^{2} : 89

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 89, x = - 89

x, f = 5 x^{2} + 4 x + 4 mn - 2

x, x^{2} + y^{2} + 2 x - 8 y + 25 = 0

(x + 1)^{2} = (x - 1)^{2} + x^{2}

x^{2} + 8 x + 16 = 49

x^{2} + 4 x - 12 = 0

What are the solutions to the equation 5^2+8^2=x^2 ?
The solutions to the equation 5^2+8^2=x^2 are x=sqrt(89),x=-sqrt(89)
Find the zeros of 5^2+8^2=x^2
The zeros of 5^2+8^2=x^2 are x=sqrt(89),x=-sqrt(89)