What are the solutions to the equation p^2+2p-11=-6 ?

The solutions to the equation p^2+2p-11=-6 are p=-1+sqrt(6),p=-1-sqrt(6)

Find the zeros of p^2+2p-11=-6

The zeros of p^2+2p-11=-6 are p=-1+sqrt(6),p=-1-sqrt(6)

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p^{2} + 2 p - 11 = - 6

p = - 1 + 6, p = - 1 - 6

Decimal Notation

p = 1.44948 \dots, p = - 3.44948 \dots

Solution steps

p^{2} + 2 p - 11 = - 6

Move

6

to the left side

p^{2} + 2 p - 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 5) = 26

p_{1, 2} = \frac{- 2 \pm 2 6}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 2 + 2 6}{2 \cdot 1}, p_{2} = \frac{- 2 - 2 6}{2 \cdot 1}

p = \frac{- 2 + 2 6}{2 \cdot 1} : - 1 + 6

p = \frac{- 2 - 2 6}{2 \cdot 1} : - 1 - 6

The solutions to the quadratic equation are:

p = - 1 + 6, p = - 1 - 6

x, y = 2 x - x^{2}

x^{2} + 2 x - 7 = 8 x

m^{2} = 0.04

6 x^{2} = 11 x + 7

x^{2} - 3 x - 5

What are the solutions to the equation p^2+2p-11=-6 ?
The solutions to the equation p^2+2p-11=-6 are p=-1+sqrt(6),p=-1-sqrt(6)
Find the zeros of p^2+2p-11=-6
The zeros of p^2+2p-11=-6 are p=-1+sqrt(6),p=-1-sqrt(6)