What are the solutions to the equation 4(2-2x)^2-43=38 ?

The solutions to the equation 4(2-2x)^2-43=38 are x=-5/4 ,x= 13/4

Find the zeros of 4(2-2x)^2-43=38

The zeros of 4(2-2x)^2-43=38 are x=-5/4 ,x= 13/4

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4 (2 - 2 x)^{2} - 43 = 38

x = - \frac{5}{4}, x = \frac{13}{4}

Decimal Notation

x = - 1.25, x = 3.25

Solution steps

4 (2 - 2 x)^{2} - 43 = 38

Move

43

to the right side

4 (2 - 2 x)^{2} = 81

Divide both sides by

4

(2 - 2 x)^{2} = \frac{81}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 - 2 x = \frac{81}{4} : x = - \frac{5}{4}

Solve

2 - 2 x = - \frac{81}{4} : x = \frac{13}{4}

The solutions to the quadratic equation are:

x = - \frac{5}{4}, x = \frac{13}{4}

12 = - 3 x^{2} + 16 x

x, \frac{x ^{2}}{25} + y^{2} = - 1

x^{2} + 2 x - 11 = - 6

3 (7 x - 2) + 3 x (x - 4) = 1

x^{2} = 1^{2} + 2^{2}

What are the solutions to the equation 4(2-2x)^2-43=38 ?
The solutions to the equation 4(2-2x)^2-43=38 are x=-5/4 ,x= 13/4
Find the zeros of 4(2-2x)^2-43=38
The zeros of 4(2-2x)^2-43=38 are x=-5/4 ,x= 13/4