What are the solutions to the equation x^2+15x-54=0 ?

The solutions to the equation x^2+15x-54=0 are x=3,x=-18

Find the zeros of x^2+15x-54=0

The zeros of x^2+15x-54=0 are x=3,x=-18

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x^{2} + 15 x - 54 = 0

x = 3, x = - 18

Solution steps

x^{2} + 15 x - 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot (- 54) = 21

x_{1, 2} = \frac{- 15 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 21}{2 \cdot 1}, x_{2} = \frac{- 15 - 21}{2 \cdot 1}

x = \frac{- 15 + 21}{2 \cdot 1} : 3

x = \frac{- 15 - 21}{2 \cdot 1} : - 18

The solutions to the quadratic equation are:

x = 3, x = - 18

4 2^{2}

lo g_{0.1} (17)

4 + \frac{x}{1 - x} \geq \frac{2}{1 - x}

- 4 + 7 x = 136

x^{2} = 2 x + 4

What are the solutions to the equation x^2+15x-54=0 ?
The solutions to the equation x^2+15x-54=0 are x=3,x=-18
Find the zeros of x^2+15x-54=0
The zeros of x^2+15x-54=0 are x=3,x=-18