What are the solutions to the equation 15x^2-75x+90=0 ?

The solutions to the equation 15x^2-75x+90=0 are x=3,x=2

Find the zeros of 15x^2-75x+90=0

The zeros of 15x^2-75x+90=0 are x=3,x=2

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15 x^{2} - 75 x + 90 = 0

x = 3, x = 2

Solution steps

15 x^{2} - 75 x + 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 75 ) \pm ( - 75 ) ^{2} - 4 \cdot 15 \cdot 90}{2 \cdot 15}

(- 75)^{2} - 4 \cdot 15 \cdot 90 = 15

x_{1, 2} = \frac{- ( - 75 ) \pm 15}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 75 ) + 15}{2 \cdot 15}, x_{2} = \frac{- ( - 75 ) - 15}{2 \cdot 15}

x = \frac{- ( - 75 ) + 15}{2 \cdot 15} : 3

x = \frac{- ( - 75 ) - 15}{2 \cdot 15} : 2

The solutions to the quadratic equation are:

x = 3, x = 2

- x^{2} + 5 x + 9 = 0

x^{2} - 20 x + 36 = 0

8^{2} + 5^{2} = x^{2}

x, x^{2} y + 6 - 3 x y = 0

4 x^{2} + 9 x = 12 x

What are the solutions to the equation 15x^2-75x+90=0 ?
The solutions to the equation 15x^2-75x+90=0 are x=3,x=2
Find the zeros of 15x^2-75x+90=0
The zeros of 15x^2-75x+90=0 are x=3,x=2