What are the solutions to the equation m^2+2m-48=-6 ?

The solutions to the equation m^2+2m-48=-6 are m=-1+sqrt(43),m=-1-sqrt(43)

Find the zeros of m^2+2m-48=-6

The zeros of m^2+2m-48=-6 are m=-1+sqrt(43),m=-1-sqrt(43)

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m^{2} + 2 m - 48 = - 6

m = - 1 + 43, m = - 1 - 43

Decimal Notation

m = 5.55743 \dots, m = - 7.55743 \dots

Solution steps

m^{2} + 2 m - 48 = - 6

Move

6

to the left side

m^{2} + 2 m - 42 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 42 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 42) = 243

m_{1, 2} = \frac{- 2 \pm 2 43}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 2 43}{2 \cdot 1}, m_{2} = \frac{- 2 - 2 43}{2 \cdot 1}

m = \frac{- 2 + 2 43}{2 \cdot 1} : - 1 + 43

m = \frac{- 2 - 2 43}{2 \cdot 1} : - 1 - 43

The solutions to the quadratic equation are:

m = - 1 + 43, m = - 1 - 43

x^{2} + 2 x = 319

y^{2} - 12 y + 36 = 49

2 a^{2} - a - 1 = 0

75 - 0.02 x = 0.000006 x^{2} - 0.02 x + 25

(x - 2) (x - 5) = 0

What are the solutions to the equation m^2+2m-48=-6 ?
The solutions to the equation m^2+2m-48=-6 are m=-1+sqrt(43),m=-1-sqrt(43)
Find the zeros of m^2+2m-48=-6
The zeros of m^2+2m-48=-6 are m=-1+sqrt(43),m=-1-sqrt(43)