What are the solutions to the equation X^2-6X+1=0 ?

The solutions to the equation X^2-6X+1=0 are X=3+2sqrt(2),X=3-2sqrt(2)

Find the zeros of X^2-6X+1=0

The zeros of X^2-6X+1=0 are X=3+2sqrt(2),X=3-2sqrt(2)

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X^{2} - 6 X + 1 = 0

X = 3 + 22, X = 3 - 22

Decimal Notation

X = 5.82842 \dots, X = 0.17157 \dots

Solution steps

X^{2} - 6 X + 1 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 1 = 42

X_{1, 2} = \frac{- ( - 6 ) \pm 4 2}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 6 ) + 4 2}{2 \cdot 1}, X_{2} = \frac{- ( - 6 ) - 4 2}{2 \cdot 1}

X = \frac{- ( - 6 ) + 4 2}{2 \cdot 1} : 3 + 22

X = \frac{- ( - 6 ) - 4 2}{2 \cdot 1} : 3 - 22

The solutions to the quadratic equation are:

X = 3 + 22, X = 3 - 22

x, 6 x^{2} y + 5 y^{3} + 3 x^{2} = 12 - x^{2} y^{2}

x^{2} + 9 x = 43.75

3 x^{2} - 24 x + 40 = 28

s^{2} - s - 2 = 0

x^{2} + 7 x = 0

What are the solutions to the equation X^2-6X+1=0 ?
The solutions to the equation X^2-6X+1=0 are X=3+2sqrt(2),X=3-2sqrt(2)
Find the zeros of X^2-6X+1=0
The zeros of X^2-6X+1=0 are X=3+2sqrt(2),X=3-2sqrt(2)