What are the solutions to the equation 121=25x^2 ?

The solutions to the equation 121=25x^2 are x= 11/5 ,x=-11/5

Find the zeros of 121=25x^2

The zeros of 121=25x^2 are x= 11/5 ,x=-11/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

121 = 25 x^{2}

x = \frac{11}{5}, x = - \frac{11}{5}

Decimal Notation

x = 2.2, x = - 2.2

Solution steps

121 = 25 x^{2}

Switch sides

25 x^{2} = 121

Divide both sides by

25

x^{2} = \frac{121}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{121}{25}, x = - \frac{121}{25}

\frac{121}{25} = \frac{11}{5}

- \frac{121}{25} = - \frac{11}{5}

x = \frac{11}{5}, x = - \frac{11}{5}

x^{2} + 12 x + 21 = 0

0 = 2 x^{2} - 2

t, s = u t + 0.5 g t^{2}

x^{2} = 18 x - 81

x^{2} + 2 x + 36 = 0

What are the solutions to the equation 121=25x^2 ?
The solutions to the equation 121=25x^2 are x= 11/5 ,x=-11/5
Find the zeros of 121=25x^2
The zeros of 121=25x^2 are x= 11/5 ,x=-11/5