What are the solutions to the equation 18-4x-5x^2=3 ?

The solutions to the equation 18-4x-5x^2=3 are x=-(2+sqrt(79))/5 ,x=(sqrt(79)-2)/5

Find the zeros of 18-4x-5x^2=3

The zeros of 18-4x-5x^2=3 are x=-(2+sqrt(79))/5 ,x=(sqrt(79)-2)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

18 - 4 x - 5 x^{2} = 3

x = - \frac{2 + 79}{5}, x = \frac{79 - 2}{5}

Decimal Notation

x = - 2.17763 \dots, x = 1.37763 \dots

Solution steps

18 - 4 x - 5 x^{2} = 3

Move

3

to the left side

- 5 x^{2} - 4 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 5 ) \cdot 15}{2 ( - 5 )}

(- 4)^{2} - 4 (- 5) \cdot 15 = 279

x_{1, 2} = \frac{- ( - 4 ) \pm 2 79}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 79}{2 ( - 5 )}, x_{2} = \frac{- ( - 4 ) - 2 79}{2 ( - 5 )}

x = \frac{- ( - 4 ) + 2 79}{2 ( - 5 )} : - \frac{2 + 79}{5}

x = \frac{- ( - 4 ) - 2 79}{2 ( - 5 )} : \frac{79 - 2}{5}

The solutions to the quadratic equation are:

x = - \frac{2 + 79}{5}, x = \frac{79 - 2}{5}

18 x^{2} - 6 x = 0

(2 x - 13)^{2} = 24

4 x^{2} - 7 x = - 5

x, 2 x^{2} + 2 y^{2} - 2 x - 2 y + 9 = 0

x^{2} + 8 x - 11 = 0

What are the solutions to the equation 18-4x-5x^2=3 ?
The solutions to the equation 18-4x-5x^2=3 are x=-(2+sqrt(79))/5 ,x=(sqrt(79)-2)/5
Find the zeros of 18-4x-5x^2=3
The zeros of 18-4x-5x^2=3 are x=-(2+sqrt(79))/5 ,x=(sqrt(79)-2)/5