What are the solutions to the equation 3r^2+8r-3=0 ?

The solutions to the equation 3r^2+8r-3=0 are r= 1/3 ,r=-3

Find the zeros of 3r^2+8r-3=0

The zeros of 3r^2+8r-3=0 are r= 1/3 ,r=-3

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3 r^{2} + 8 r - 3 = 0

r = \frac{1}{3}, r = - 3

Decimal Notation

r = 0.33333 \dots, r = - 3

Solution steps

3 r^{2} + 8 r - 3 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 3) = 10

r_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 3}

Separate the solutions

r_{1} = \frac{- 8 + 10}{2 \cdot 3}, r_{2} = \frac{- 8 - 10}{2 \cdot 3}

r = \frac{- 8 + 10}{2 \cdot 3} : \frac{1}{3}

r = \frac{- 8 - 10}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

r = \frac{1}{3}, r = - 3

x^{2} + 2 x - 5 = 0

x^{2} - 18 x + 86 = 0

3 x^{2} + 17 x - 28 = 0

x^{2} - 4 x = - 7

0 = 3 x^{2} - 4

What are the solutions to the equation 3r^2+8r-3=0 ?
The solutions to the equation 3r^2+8r-3=0 are r= 1/3 ,r=-3
Find the zeros of 3r^2+8r-3=0
The zeros of 3r^2+8r-3=0 are r= 1/3 ,r=-3