What are the solutions to the equation 6+(p+8)^2=31 ?

The solutions to the equation 6+(p+8)^2=31 are p=-3,p=-13

Find the zeros of 6+(p+8)^2=31

The zeros of 6+(p+8)^2=31 are p=-3,p=-13

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6 + (p + 8)^{2} = 31

p = - 3, p = - 13

Solution steps

6 + (p + 8)^{2} = 31

Move

6

to the right side

(p + 8)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

p + 8 = 25 : p = - 3

Solve

p + 8 = - 25 : p = - 13

The solutions to the quadratic equation are:

p = - 3, p = - 13

x^{2} = 20 x

4 x^{2} + 8 x + 6 = 0

(2 x - 5)^{2} - (x - 6)^{2} = 80

(m - 5) (m - 4) = 0

x^{2} + 26 x = - 88

What are the solutions to the equation 6+(p+8)^2=31 ?
The solutions to the equation 6+(p+8)^2=31 are p=-3,p=-13
Find the zeros of 6+(p+8)^2=31
The zeros of 6+(p+8)^2=31 are p=-3,p=-13