What are the solutions to the equation (x-1)(4x-5)=0 ?

The solutions to the equation (x-1)(4x-5)=0 are x=1,x= 5/4

Find the zeros of (x-1)(4x-5)=0

The zeros of (x-1)(4x-5)=0 are x=1,x= 5/4

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(x - 1) (4 x - 5) = 0

x = 1, x = \frac{5}{4}

Decimal Notation

x = 1, x = 1.25

Solution steps

(x - 1) (4 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 4 x - 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

4 x - 5 = 0 : x = \frac{5}{4}

The solutions to the quadratic equation are:

x = 1, x = \frac{5}{4}

7 x^{2} - 9 = 0

6 x (x - 1) + 4 (x + 4) (x - 1) = (2 x + 2) (x + 4)

x^{2} + 1 = - 99

x^{2} - x - 20 = 0

2 x^{2} - 3 x = 4

What are the solutions to the equation (x-1)(4x-5)=0 ?
The solutions to the equation (x-1)(4x-5)=0 are x=1,x= 5/4
Find the zeros of (x-1)(4x-5)=0
The zeros of (x-1)(4x-5)=0 are x=1,x= 5/4