What are the solutions to the equation x^2+11=12x ?

The solutions to the equation x^2+11=12x are x=11,x=1

Find the zeros of x^2+11=12x

The zeros of x^2+11=12x are x=11,x=1

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x^{2} + 11 = 12 x

x = 11, x = 1

Solution steps

x^{2} + 11 = 12 x

Move

12 x

to the left side

x^{2} + 11 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 12 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 11 = 10

x_{1, 2} = \frac{- ( - 12 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 10}{2 \cdot 1}

x = \frac{- ( - 12 ) + 10}{2 \cdot 1} : 11

x = \frac{- ( - 12 ) - 10}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 11, x = 1

3 x^{2} - 12 x - 9 = 0

4 x^{2} - 9 x + 9 = 0

20 + 8 y = 5 y^{2}

x, x^{2} y^{2} - x^{2} + y^{2} + 1 = 0

36 x^{2} = 4

What are the solutions to the equation x^2+11=12x ?
The solutions to the equation x^2+11=12x are x=11,x=1
Find the zeros of x^2+11=12x
The zeros of x^2+11=12x are x=11,x=1