What are the solutions to the equation 3x=x^2-10 ?

The solutions to the equation 3x=x^2-10 are x=5,x=-2

Find the zeros of 3x=x^2-10

The zeros of 3x=x^2-10 are x=5,x=-2

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3 x = x^{2} - 10

x = 5, x = - 2

Solution steps

3 x = x^{2} - 10

Switch sides

x^{2} - 10 = 3 x

Move

3 x

to the left side

x^{2} - 10 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

x = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

x = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 5, x = - 2

2 + 3 x = - 1

- 2 x = (x + 1) (x - 1) + (4 x^{2} - 2)

\frac{1}{4} + \frac{1}{7}

\frac{1}{\frac{2}{4}}

What are the solutions to the equation 3x=x^2-10 ?
The solutions to the equation 3x=x^2-10 are x=5,x=-2
Find the zeros of 3x=x^2-10
The zeros of 3x=x^2-10 are x=5,x=-2