What are the solutions to the equation quadraticformula x^2-2x-8=0 ?

The solutions to the equation quadraticformula x^2-2x-8=0 are x=4,x=-2

Find the zeros of quadraticformula x^2-2x-8=0

The zeros of quadraticformula x^2-2x-8=0 are x=4,x=-2

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x^{2} - 2 x - 8 = 0

x = 4, x = - 2

Solution steps

x^{2} - 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 8) = 6

x_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 6}{2 \cdot 1} : 4

x = \frac{- ( - 2 ) - 6}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 4, x = - 2

12 x^{2} - 42 x + 36 = 0

x, 5 x^{2} + 5 y^{2} + 6 x y = 8

3 x^{2} - 19 x + 6 = 0

y^{2} - 2 y + 5 = 0

x^{2} - 6 x + 11

What are the solutions to the equation quadraticformula x^2-2x-8=0 ?
The solutions to the equation quadraticformula x^2-2x-8=0 are x=4,x=-2
Find the zeros of quadraticformula x^2-2x-8=0
The zeros of quadraticformula x^2-2x-8=0 are x=4,x=-2