What are the solutions to the equation 40^2+x^2=41^2 ?

The solutions to the equation 40^2+x^2=41^2 are x=9,x=-9

Find the zeros of 40^2+x^2=41^2

The zeros of 40^2+x^2=41^2 are x=9,x=-9

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4 0^{2} + x^{2} = 4 1^{2}

x = 9, x = - 9

Solution steps

4 0^{2} + x^{2} = 4 1^{2}

Move

4 0^{2}

to the right side

x^{2} = 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 81, x = - 81

81 = 9

- 81 = - 9

x = 9, x = - 9

3 m^{2} + 5 m = 6

2 m^{2} - 3 m - 4 = 0

0 = 6 x^{2} - 6 x - 12

2 x^{2} - x = 5

x, x^{2} + y^{2} + 8 x - 14 y + 66 = 0

What are the solutions to the equation 40^2+x^2=41^2 ?
The solutions to the equation 40^2+x^2=41^2 are x=9,x=-9
Find the zeros of 40^2+x^2=41^2
The zeros of 40^2+x^2=41^2 are x=9,x=-9