What are the solutions to the equation (x+1)^2-225=0 ?

The solutions to the equation (x+1)^2-225=0 are x=14,x=-16

Find the zeros of (x+1)^2-225=0

The zeros of (x+1)^2-225=0 are x=14,x=-16

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(x + 1)^{2} - 225 = 0

x = 14, x = - 16

Solution steps

(x + 1)^{2} - 225 = 0

Move

225

to the right side

(x + 1)^{2} = 225

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 225 : x = 14

Solve

x + 1 = - 225 : x = - 16

The solutions to the quadratic equation are:

x = 14, x = - 16

5 x^{2} + 4 = 7 x

p (p - 3) 2 - 4 (p - 3) 3 = 0

a, x^{2} + a^{2} y^{2} = 4 a^{2}

3 x^{2} + 24 x + 45 = 0

x, 2 x^{2} + 5 x - 3 = 0

What are the solutions to the equation (x+1)^2-225=0 ?
The solutions to the equation (x+1)^2-225=0 are x=14,x=-16
Find the zeros of (x+1)^2-225=0
The zeros of (x+1)^2-225=0 are x=14,x=-16