What are the solutions to the equation solvefor x,y=-(x-2)^2+9 ?

The solutions to the equation solvefor x,y=-(x-2)^2+9 are x=sqrt(-y+9)+2,x=-sqrt(-y+9)+2

Find the zeros of solvefor x,y=-(x-2)^2+9

The zeros of solvefor x,y=-(x-2)^2+9 are x=sqrt(-y+9)+2,x=-sqrt(-y+9)+2

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solve for

x, y = - (x - 2)^{2} + 9

x = - y + 9 + 2, x = - - y + 9 + 2

Solution steps

y = - (x - 2)^{2} + 9

Switch sides

- (x - 2)^{2} + 9 = y

Move

9

to the right side

- (x - 2)^{2} = y - 9

Divide both sides by

- 1

(x - 2)^{2} = - y + 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - y + 9 : x = - y + 9 + 2

Solve

x - 2 = - - y + 9 : x = - - y + 9 + 2

The solutions to the quadratic equation are:

x = - y + 9 + 2, x = - - y + 9 + 2

- 11 x + 2 = x^{2} + 30

x, x^{2} y^{2} + x y = 5

3 x^{2} + 42 x = - 105

3 x^{2} - 13 = 0

4 5^{2} + 2 8^{2} = x^{2}

What are the solutions to the equation solvefor x,y=-(x-2)^2+9 ?
The solutions to the equation solvefor x,y=-(x-2)^2+9 are x=sqrt(-y+9)+2,x=-sqrt(-y+9)+2
Find the zeros of solvefor x,y=-(x-2)^2+9
The zeros of solvefor x,y=-(x-2)^2+9 are x=sqrt(-y+9)+2,x=-sqrt(-y+9)+2