What are the solutions to the equation y^2+5y-6=0 ?

The solutions to the equation y^2+5y-6=0 are y=1,y=-6

Find the zeros of y^2+5y-6=0

The zeros of y^2+5y-6=0 are y=1,y=-6

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y^{2} + 5 y - 6 = 0

y = 1, y = - 6

Solution steps

y^{2} + 5 y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 6) = 7

y_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 5 + 7}{2 \cdot 1}, y_{2} = \frac{- 5 - 7}{2 \cdot 1}

y = \frac{- 5 + 7}{2 \cdot 1} : 1

y = \frac{- 5 - 7}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

y = 1, y = - 6

\frac{1}{2} (x + 4)^{2} - 3 = 29

x^{2} - 12 x - 12 = - 39

x, x^{2} - 2 x - 1 = 0

3 x^{2} = 1.47

x, z = 25 - x^{2} - y^{2}

What are the solutions to the equation y^2+5y-6=0 ?
The solutions to the equation y^2+5y-6=0 are y=1,y=-6
Find the zeros of y^2+5y-6=0
The zeros of y^2+5y-6=0 are y=1,y=-6