What are the solutions to the equation x^2+76=18x ?

The solutions to the equation x^2+76=18x are x=9+sqrt(5),x=9-sqrt(5)

Find the zeros of x^2+76=18x

The zeros of x^2+76=18x are x=9+sqrt(5),x=9-sqrt(5)

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x^{2} + 76 = 18 x

x = 9 + 5, x = 9 - 5

Decimal Notation

x = 11.23606 \dots, x = 6.76393 \dots

Solution steps

x^{2} + 76 = 18 x

Move

18 x

to the left side

x^{2} + 76 - 18 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 18 x + 76 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 76}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 76 = 25

x_{1, 2} = \frac{- ( - 18 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 5}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 5}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 5}{2 \cdot 1} : 9 + 5

x = \frac{- ( - 18 ) - 2 5}{2 \cdot 1} : 9 - 5

The solutions to the quadratic equation are:

x = 9 + 5, x = 9 - 5

x^{2} - 14 x + 49 = 9

3 x^{2} - 12 x + 6 = 0

k^{2} - 5 k + 6 = 0

5 (4 x - 10)^{2} + 19 = 44

4 x^{2} + 4 x + 1

What are the solutions to the equation x^2+76=18x ?
The solutions to the equation x^2+76=18x are x=9+sqrt(5),x=9-sqrt(5)
Find the zeros of x^2+76=18x
The zeros of x^2+76=18x are x=9+sqrt(5),x=9-sqrt(5)