What is (2x+1)/(3x-1)>= (2x+5)/(3x+2) ?

The solution to (2x+1)/(3x-1)>= (2x+5)/(3x+2) is x<-2/3 \lor 1/3 <x<= 7/6

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(2x+1)/(3x-1)>= (2x+5)/(3x+2)

\frac{2 x + 1}{3 x - 1} \geq \frac{2 x + 5}{3 x + 2}

x < - \frac{2}{3} or \frac{1}{3} < x \leq \frac{7}{6}

Interval Notation

(- \infty, - \frac{2}{3}) \cup (\frac{1}{3}, \frac{7}{6}]

Decimal Notation

x < - 0.66666 \dots or 0.33333 \dots < x \leq 1.16666 \dots

Solution steps

\frac{2 x + 1}{3 x - 1} \geq \frac{2 x + 5}{3 x + 2}

Rewrite in standard form

\frac{- 6 x + 7}{( 3 x - 1 ) ( 3 x + 2 )} \geq 0

Identify the intervals

x < - \frac{2}{3} or \frac{1}{3} < x \leq \frac{7}{6}

7 = - \frac{5}{4} (8) + b

x^{2} - 2 x - 28 = 0

∣ 5 - 2 x ∣ \leq 7

3 z^{2} + 10 z + 3

∣ x + 4 ∣ = 8

What is (2x+1)/(3x-1)>= (2x+5)/(3x+2) ?
The solution to (2x+1)/(3x-1)>= (2x+5)/(3x+2) is x<-2/3 \lor 1/3 <x<= 7/6