What are the solutions to the equation a^2+10a+25=0 ?

The solutions to the equation a^2+10a+25=0 are a=-5

Find the zeros of a^2+10a+25=0

The zeros of a^2+10a+25=0 are a=-5

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a^{2} + 10 a + 25 = 0

a = - 5

Solution steps

a^{2} + 10 a + 25 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

a_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

a = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

a = - 5

The solution to the quadratic equation is:

a = - 5

- 3 x^{2} + 9 x = 0

y^{2} - y

4 x^{2} - 8 x + 12

10 x^{2} - 20 = 0

9 (3 x - 7)^{2} = 16

What are the solutions to the equation a^2+10a+25=0 ?
The solutions to the equation a^2+10a+25=0 are a=-5
Find the zeros of a^2+10a+25=0
The zeros of a^2+10a+25=0 are a=-5