What are the solutions to the equation -(4x-5)^2+3=-3 ?

The solutions to the equation -(4x-5)^2+3=-3 are x=(sqrt(6)+5)/4 ,x=(-sqrt(6)+5)/4

Find the zeros of -(4x-5)^2+3=-3

The zeros of -(4x-5)^2+3=-3 are x=(sqrt(6)+5)/4 ,x=(-sqrt(6)+5)/4

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- (4 x - 5)^{2} + 3 = - 3

x = \frac{6 + 5}{4}, x = \frac{- 6 + 5}{4}

Decimal Notation

x = 1.86237 \dots, x = 0.63762 \dots

Solution steps

- (4 x - 5)^{2} + 3 = - 3

Move

3

to the right side

- (4 x - 5)^{2} = - 6

Divide both sides by

- 1

(4 x - 5)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 5 = 6 : x = \frac{6 + 5}{4}

Solve

4 x - 5 = - 6 : x = \frac{- 6 + 5}{4}

The solutions to the quadratic equation are:

x = \frac{6 + 5}{4}, x = \frac{- 6 + 5}{4}

3 x^{2} + 6 x = - 2

x^{2} - 7 = 4 x

5 x^{2} = - 9 x - 6

x, x^{2} + y^{2} - 2 x + 6 y + 11 = 0

2 x^{2} - 5 x = 3 (x + 4)

What are the solutions to the equation -(4x-5)^2+3=-3 ?
The solutions to the equation -(4x-5)^2+3=-3 are x=(sqrt(6)+5)/4 ,x=(-sqrt(6)+5)/4
Find the zeros of -(4x-5)^2+3=-3
The zeros of -(4x-5)^2+3=-3 are x=(sqrt(6)+5)/4 ,x=(-sqrt(6)+5)/4