What are the solutions to the equation abx^2+ab=x(a^2+b^2) ?

The solutions to the equation abx^2+ab=x(a^2+b^2) are x= a/b ,x= b/a ;\quad ab\ne 0

Find the zeros of abx^2+ab=x(a^2+b^2)

The zeros of abx^2+ab=x(a^2+b^2) are x= a/b ,x= b/a ;\quad ab\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ab x^{2} + ab = x (a^{2} + b^{2})

x = \frac{a}{b}, x = \frac{b}{a}; ab \neq = 0

Solution steps

ab x^{2} + ab = x (a^{2} + b^{2})

Move

x (a^{2} + b^{2})

to the left side

ab x^{2} + ab - x (a^{2} + b^{2}) = 0

Write in the standard form

a x^{2} + b x + c = 0

ab x^{2} - (a^{2} + b^{2}) x + ab = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - a ^{2} - b ^{2} ) \pm ( - a ^{2} - b ^{2} ) ^{2} - 4 abab}{2 ab}

Simplify

(- a^{2} - b^{2})^{2} - 4 abab : (a + b) (a - b)

x_{1, 2} = \frac{- ( - a ^{2} - b ^{2} ) \pm ( a + b ) ( a - b )}{2 ab}; ab \neq = 0

Separate the solutions

x_{1} = \frac{- ( - a ^{2} - b ^{2} ) + ( a + b ) ( a - b )}{2 ab}, x_{2} = \frac{- ( - a ^{2} - b ^{2} ) - ( a + b ) ( a - b )}{2 ab}

x = \frac{- ( - a ^{2} - b ^{2} ) + ( a + b ) ( a - b )}{2 ab} : \frac{a}{b}

x = \frac{- ( - a ^{2} - b ^{2} ) - ( a + b ) ( a - b )}{2 ab} : \frac{b}{a}

The solutions to the quadratic equation are:

x = \frac{a}{b}, x = \frac{b}{a}; ab \neq = 0

x^{2} = \frac{7}{5}

s^{2} - 6 s + 10

x, - 3 x^{2} + 2 x y + y^{2} = 0

(x + 2)^{2} - 3 = x - 2

w, w 0.5 w + 9 z = 2 z + 3 w

What are the solutions to the equation abx^2+ab=x(a^2+b^2) ?
The solutions to the equation abx^2+ab=x(a^2+b^2) are x= a/b ,x= b/a ;\quad ab\ne 0
Find the zeros of abx^2+ab=x(a^2+b^2)
The zeros of abx^2+ab=x(a^2+b^2) are x= a/b ,x= b/a ;\quad ab\ne 0