What are the solutions to the equation -7x^2+12x+64=0 ?

The solutions to the equation -7x^2+12x+64=0 are x=-16/7 ,x=4

Find the zeros of -7x^2+12x+64=0

The zeros of -7x^2+12x+64=0 are x=-16/7 ,x=4

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- 7 x^{2} + 12 x + 64 = 0

x = - \frac{16}{7}, x = 4

Decimal Notation

x = - 2.28571 \dots, x = 4

Solution steps

- 7 x^{2} + 12 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 7 ) \cdot 64}{2 ( - 7 )}

1 2^{2} - 4 (- 7) \cdot 64 = 44

x_{1, 2} = \frac{- 12 \pm 44}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 12 + 44}{2 ( - 7 )}, x_{2} = \frac{- 12 - 44}{2 ( - 7 )}

x = \frac{- 12 + 44}{2 ( - 7 )} : - \frac{16}{7}

x = \frac{- 12 - 44}{2 ( - 7 )} : 4

The solutions to the quadratic equation are:

x = - \frac{16}{7}, x = 4

- 3 x^{2} - 9 = - 5 x

10 x^{2} - 50 = 0

0.3 x^{2} + 1.6 x - 1.3 = 0

2 x^{2} + 9 x - 35 = 0

35 x^{2} + 12 x - 36 = 0

What are the solutions to the equation -7x^2+12x+64=0 ?
The solutions to the equation -7x^2+12x+64=0 are x=-16/7 ,x=4
Find the zeros of -7x^2+12x+64=0
The zeros of -7x^2+12x+64=0 are x=-16/7 ,x=4