What are the solutions to the equation x^2-x+1/4 =0 ?

The solutions to the equation x^2-x+1/4 =0 are x= 1/2

Find the zeros of x^2-x+1/4 =0

The zeros of x^2-x+1/4 =0 are x= 1/2

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x^{2} - x + \frac{1}{4} = 0

x = \frac{1}{2}

Solution steps

x^{2} - x + \frac{1}{4} = 0

Multiply both sides by

4

4 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

∣ x ∣ \geq 7

- 3 (m - 2) + 9 (m + 5) = 8 m + 31

14 = \frac{1}{2} (9 x - 8)

- \frac{3 π}{4} - 2 π

8 > 8

What are the solutions to the equation x^2-x+1/4 =0 ?
The solutions to the equation x^2-x+1/4 =0 are x= 1/2
Find the zeros of x^2-x+1/4 =0
The zeros of x^2-x+1/4 =0 are x= 1/2