What are the solutions to the equation m^2-m+1/4 =0 ?

The solutions to the equation m^2-m+1/4 =0 are m= 1/2

Find the zeros of m^2-m+1/4 =0

The zeros of m^2-m+1/4 =0 are m= 1/2

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m^{2} - m + \frac{1}{4} = 0

m = \frac{1}{2}

Decimal Notation

m = 0.5

Solution steps

m^{2} - m + \frac{1}{4} = 0

Multiply both sides by

4

4 m^{2} - 4 m + 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

m_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

m = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

m = \frac{1}{2}

The solution to the quadratic equation is:

m = \frac{1}{2}

2 x^{2} + 10 x - 28 = 0

3 m^{2} + 1 = 0

x^{2} - 5 x + 5.25 = 0

x^{2} = (x \cdot 110)^{2} + 1.7 3^{2}

(5 x - 2)^{2} = 2 (4 x - 6)

What are the solutions to the equation m^2-m+1/4 =0 ?
The solutions to the equation m^2-m+1/4 =0 are m= 1/2
Find the zeros of m^2-m+1/4 =0
The zeros of m^2-m+1/4 =0 are m= 1/2