What are the solutions to the equation 3x^2+54=0 ?

The solutions to the equation 3x^2+54=0 are x=sqrt(2)*3i,x=-sqrt(2)*3i

Find the zeros of 3x^2+54=0

The zeros of 3x^2+54=0 are x=sqrt(2)*3i,x=-sqrt(2)*3i

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3 x^{2} + 54 = 0

x = 2 \cdot 3 i, x = - 2 \cdot 3 i

Solution steps

3 x^{2} + 54 = 0

Move

54

to the right side

3 x^{2} = - 54

Divide both sides by

3

x^{2} = - 18

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 18, x = - - 18

- 18 = 2 \cdot 3 i

- - 18 = - 2 \cdot 3 i

x = 2 \cdot 3 i, x = - 2 \cdot 3 i

y, (x - h)^{2} + (y - k)^{2} = r^{2}

5 (c + 1)^{2} = 25

9 x + 5 = 4 (x^{2} - 1)

x, x^{2} + 14 x y + 49 y^{2} = 100

- 2 x^{2} + 2 x + 3 = 0

What are the solutions to the equation 3x^2+54=0 ?
The solutions to the equation 3x^2+54=0 are x=sqrt(2)*3i,x=-sqrt(2)*3i
Find the zeros of 3x^2+54=0
The zeros of 3x^2+54=0 are x=sqrt(2)*3i,x=-sqrt(2)*3i