What are the solutions to the equation 2x(x+7)=9x-1 ?

The solutions to the equation 2x(x+7)=9x-1 are x=(-5+sqrt(17))/4 ,x=(-5-sqrt(17))/4

Find the zeros of 2x(x+7)=9x-1

The zeros of 2x(x+7)=9x-1 are x=(-5+sqrt(17))/4 ,x=(-5-sqrt(17))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x (x + 7) = 9 x - 1

x = \frac{- 5 + 17}{4}, x = \frac{- 5 - 17}{4}

Decimal Notation

x = - 0.21922 \dots, x = - 2.28077 \dots

Solution steps

2 x (x + 7) = 9 x - 1

Expand

2 x (x + 7) : 2 x^{2} + 14 x

2 x^{2} + 14 x = 9 x - 1

Move

1

to the left side

2 x^{2} + 14 x + 1 = 9 x

Move

9 x

to the left side

2 x^{2} + 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

5^{2} - 4 \cdot 2 \cdot 1 = 17

x_{1, 2} = \frac{- 5 \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 17}{2 \cdot 2}, x_{2} = \frac{- 5 - 17}{2 \cdot 2}

x = \frac{- 5 + 17}{2 \cdot 2} : \frac{- 5 + 17}{4}

x = \frac{- 5 - 17}{2 \cdot 2} : \frac{- 5 - 17}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 17}{4}, x = \frac{- 5 - 17}{4}

x, x^{2} - x y + y^{2} - 2 x + 6 y - 16 = 0

2 x^{2} + 32 x + 16 = 0

x^{2} + 15 x - 18 = 8 x

36 + 5 x - x^{2} = 0

z^{2} - 4 z

What are the solutions to the equation 2x(x+7)=9x-1 ?
The solutions to the equation 2x(x+7)=9x-1 are x=(-5+sqrt(17))/4 ,x=(-5-sqrt(17))/4
Find the zeros of 2x(x+7)=9x-1
The zeros of 2x(x+7)=9x-1 are x=(-5+sqrt(17))/4 ,x=(-5-sqrt(17))/4