What are the solutions to the equation x^2+12x-12=0 ?

The solutions to the equation x^2+12x-12=0 are x=2(2sqrt(3)-3),x=-2(3+2sqrt(3))

Find the zeros of x^2+12x-12=0

The zeros of x^2+12x-12=0 are x=2(2sqrt(3)-3),x=-2(3+2sqrt(3))

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x^{2} + 12 x - 12 = 0

x = 2 (23 - 3), x = - 2 (3 + 23)

Decimal Notation

x = 0.92820 \dots, x = - 12.92820 \dots

Solution steps

x^{2} + 12 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 12) = 83

x_{1, 2} = \frac{- 12 \pm 8 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 8 3}{2 \cdot 1}, x_{2} = \frac{- 12 - 8 3}{2 \cdot 1}

x = \frac{- 12 + 8 3}{2 \cdot 1} : 2 (23 - 3)

x = \frac{- 12 - 8 3}{2 \cdot 1} : - 2 (3 + 23)

The solutions to the quadratic equation are:

x = 2 (23 - 3), x = - 2 (3 + 23)

3 x^{2} + 4 x + c = 0

7 x^{2} + 28 x + 56 = 0

(x + 2) (x - 2) (x^{2} - 3) = (x^{2} - 4) (x^{2} + 3)

x^{2} + 10 x + 16 = 15

y, x^{3} + x^{2} y + 3 y^{2} = 2

What are the solutions to the equation x^2+12x-12=0 ?
The solutions to the equation x^2+12x-12=0 are x=2(2sqrt(3)-3),x=-2(3+2sqrt(3))
Find the zeros of x^2+12x-12=0
The zeros of x^2+12x-12=0 are x=2(2sqrt(3)-3),x=-2(3+2sqrt(3))