What are the solutions to the equation 9x^2-6x+38=0 ?

The solutions to the equation 9x^2-6x+38=0 are x= 1/3+i(sqrt(37))/3 ,x= 1/3-i(sqrt(37))/3

Find the zeros of 9x^2-6x+38=0

The zeros of 9x^2-6x+38=0 are x= 1/3+i(sqrt(37))/3 ,x= 1/3-i(sqrt(37))/3

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9 x^{2} - 6 x + 38 = 0

x = \frac{1}{3} + i \frac{37}{3}, x = \frac{1}{3} - i \frac{37}{3}

Solution steps

9 x^{2} - 6 x + 38 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 \cdot 38}{2 \cdot 9}

Simplify

(- 6)^{2} - 4 \cdot 9 \cdot 38 : 637 i

x_{1, 2} = \frac{- ( - 6 ) \pm 6 37 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 37 i}{2 \cdot 9}, x_{2} = \frac{- ( - 6 ) - 6 37 i}{2 \cdot 9}

x = \frac{- ( - 6 ) + 6 37 i}{2 \cdot 9} : \frac{1}{3} + i \frac{37}{3}

x = \frac{- ( - 6 ) - 6 37 i}{2 \cdot 9} : \frac{1}{3} - i \frac{37}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{37}{3}, x = \frac{1}{3} - i \frac{37}{3}

s^{2} - 4 s + 13

2 x^{2} - 6 x = 6 x^{2} - 8 x

x, 2 z = x^{2} + y^{2}

4 x^{2} + 4 x + 1 = 121

\frac{1}{2} (x - 4)^{2} + 3 = 30

What are the solutions to the equation 9x^2-6x+38=0 ?
The solutions to the equation 9x^2-6x+38=0 are x= 1/3+i(sqrt(37))/3 ,x= 1/3-i(sqrt(37))/3
Find the zeros of 9x^2-6x+38=0
The zeros of 9x^2-6x+38=0 are x= 1/3+i(sqrt(37))/3 ,x= 1/3-i(sqrt(37))/3