What are the solutions to the equation -2x^2+9x+29=-6 ?

The solutions to the equation -2x^2+9x+29=-6 are x=-5/2 ,x=7

Find the zeros of -2x^2+9x+29=-6

The zeros of -2x^2+9x+29=-6 are x=-5/2 ,x=7

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- 2 x^{2} + 9 x + 29 = - 6

x = - \frac{5}{2}, x = 7

Decimal Notation

x = - 2.5, x = 7

Solution steps

- 2 x^{2} + 9 x + 29 = - 6

Move

6

to the left side

- 2 x^{2} + 9 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 2 ) \cdot 35}{2 ( - 2 )}

9^{2} - 4 (- 2) \cdot 35 = 19

x_{1, 2} = \frac{- 9 \pm 19}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 9 + 19}{2 ( - 2 )}, x_{2} = \frac{- 9 - 19}{2 ( - 2 )}

x = \frac{- 9 + 19}{2 ( - 2 )} : - \frac{5}{2}

x = \frac{- 9 - 19}{2 ( - 2 )} : 7

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = 7

x, 2 x^{2} - 3 x y + 3 y^{2} = 50

11 r + 15 = - 2 r^{2}

12 x - 2 x^{2} = 0

x, x^{2} + 2 x y + y^{2} = 0

- 11 x^{2} + 2 x = 10

What are the solutions to the equation -2x^2+9x+29=-6 ?
The solutions to the equation -2x^2+9x+29=-6 are x=-5/2 ,x=7
Find the zeros of -2x^2+9x+29=-6
The zeros of -2x^2+9x+29=-6 are x=-5/2 ,x=7