What are the solutions to the equation 2n^2+10n+7=0 ?

The solutions to the equation 2n^2+10n+7=0 are n=(-5+sqrt(11))/2 ,n=-(5+sqrt(11))/2

Find the zeros of 2n^2+10n+7=0

The zeros of 2n^2+10n+7=0 are n=(-5+sqrt(11))/2 ,n=-(5+sqrt(11))/2

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2 n^{2} + 10 n + 7 = 0

n = \frac{- 5 + 11}{2}, n = - \frac{5 + 11}{2}

Decimal Notation

n = - 0.84168 \dots, n = - 4.15831 \dots

Solution steps

2 n^{2} + 10 n + 7 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 \cdot 7 = 211

n_{1, 2} = \frac{- 10 \pm 2 11}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- 10 + 2 11}{2 \cdot 2}, n_{2} = \frac{- 10 - 2 11}{2 \cdot 2}

n = \frac{- 10 + 2 11}{2 \cdot 2} : \frac{- 5 + 11}{2}

n = \frac{- 10 - 2 11}{2 \cdot 2} : - \frac{5 + 11}{2}

The solutions to the quadratic equation are:

n = \frac{- 5 + 11}{2}, n = - \frac{5 + 11}{2}

12 x^{2} - 7 x - 10 = 0

- 12 x^{2} + 16 = 0

x, x^{2} + 3 x + 2 = 0

3 x^{2} - 2 x + 6 = 0

0 = 3 x^{2} - 6 x + 2

What are the solutions to the equation 2n^2+10n+7=0 ?
The solutions to the equation 2n^2+10n+7=0 are n=(-5+sqrt(11))/2 ,n=-(5+sqrt(11))/2
Find the zeros of 2n^2+10n+7=0
The zeros of 2n^2+10n+7=0 are n=(-5+sqrt(11))/2 ,n=-(5+sqrt(11))/2