What are the solutions to the equation 5x^2+3=x ?

The solutions to the equation 5x^2+3=x are x= 1/10+i(sqrt(59))/(10),x= 1/10-i(sqrt(59))/(10)

Find the zeros of 5x^2+3=x

The zeros of 5x^2+3=x are x= 1/10+i(sqrt(59))/(10),x= 1/10-i(sqrt(59))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} + 3 = x

x = \frac{1}{10} + i \frac{59}{10}, x = \frac{1}{10} - i \frac{59}{10}

Solution steps

5 x^{2} + 3 = x

Move

x

to the left side

5 x^{2} + 3 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

Simplify

(- 1)^{2} - 4 \cdot 5 \cdot 3 : 59 i

x_{1, 2} = \frac{- ( - 1 ) \pm 59 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 59 i}{2 \cdot 5}, x_{2} = \frac{- ( - 1 ) - 59 i}{2 \cdot 5}

x = \frac{- ( - 1 ) + 59 i}{2 \cdot 5} : \frac{1}{10} + i \frac{59}{10}

x = \frac{- ( - 1 ) - 59 i}{2 \cdot 5} : \frac{1}{10} - i \frac{59}{10}

The solutions to the quadratic equation are:

x = \frac{1}{10} + i \frac{59}{10}, x = \frac{1}{10} - i \frac{59}{10}

5 x^{2} + 2 = 6

x^{2} - 3 x + 5

x^{2} - 3 x + 1

x^{2} - 53 = - 98

1^{2} + b^{2} = 4^{2}

What are the solutions to the equation 5x^2+3=x ?
The solutions to the equation 5x^2+3=x are x= 1/10+i(sqrt(59))/(10),x= 1/10-i(sqrt(59))/(10)
Find the zeros of 5x^2+3=x
The zeros of 5x^2+3=x are x= 1/10+i(sqrt(59))/(10),x= 1/10-i(sqrt(59))/(10)